Բերման բանաձևեր

sin(90°+α)=cos α

sin(90°−α)=cos αcos(90°+α)= -sin αcos(90°−α)=sin αsin(180°−α)=sin αcos(180°−α)= −cos αtg(90°+α)= -ctg αtg(90°-α)=ctg α

sin 30°=1/2sin 60°=√3/2cos 30°=√3/2cos 60°=1/2tg 30°=1/2 : √3/2=1/√3=√3/3tg 60°=√3/2 : 1/2=√3ctg 30°=√3/2 : 1/2=√3ctg 60°=1/2 : √3/2=√3/3

sin 45°=√2/2cos 45°=√2/2tg 45°=√2/2 : √2/2=1ctg 45°=√2/2 : √2/2=1Վարժ․ 303

1) 120°sin 120°=sin(90°+α)=cos 30°cos 30°=√3/2cos(90°+α)= -sin α= -sin 30°-sin 30°= -1/2tg 120°=√3/2 : (-1/2)= -√32) 135°sin 135°=sin(90°+α)=cos 45°cos 45°=√2/2cos(90°+α)= -sin α= -sin 45°-sin 45°= -√2/2tg 135°=√2/2 : (-√2/2)= -13) 150°sin 150°=sin(90°+α)=cos 60°cos 60°=1/2cos(90°+α)= -sin α= -sin 60°-sin 60°= -√3/2tg 150°=1/2 : (-√3/2)= -√3/3